Science Junction

Water What-ifs
Water Quality and Temperature

Try this practice problem:

Human body temperature is normally 98.6°F. What is this on the Celsius scale?

T(°C) = [T(°F)-32] / 1.80

T(°C) = [98.6 - 32] /1.80

T(°C) = [66.6] / 1.80

T(°C) = 37.0

Since 98.6°F is 66.6°F above freezing, the Celsius temperature is 37.0°C.

 
| Temperature Conversion | Water Quality and Temperature | Water What-ifs Home |
 

e-mail the author
©1998 April J. Cleveland for Science Junction, NC State University. All rights reserved.
page design by Lisa Leonor Grable and April J. Cleveland
URL: http://www.ncsu.edu/sciencejunction/depot/experiments/water/lessons/temp/tempprob.html
Last Modified: 6/11/98

Data Depot  | Science Junction  | NC State University |